(d^2x)/(dt^2)+16*x=0

Lösung

\frac{d ^{2} x}{d t ^{2}} + 16 \cdot x = 0

x = c_{1} cos (4 t) + c_{2} sin (4 t)

Schritte zur Lösung

\frac{d ^{2} x}{d t ^{2}} + 16 \cdot x = 0

Solve linear ODE:

x = c_{1} cos (4 t) + c_{2} sin (4 t)

x = c_{1} cos (4 t) + c_{2} sin (4 t)

y^{^{''}} - 2 y^{^{'}} - 8 y = 0, y (0) = a, y^{^{'}} (0) = 5

x^{^{''}} + 4 x^{^{'}} + 29 x = 0

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 2

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = \frac{33}{4}

81 y^{^{''}} = - 16 y