y^{''}+5y+4y=0

Lösung

y^{^{''}} + 5 y + 4 y = 0

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Schritte zur Lösung

y^{''} (t) + 5 y + 4 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

\frac{1}{4} \frac{d ^{2} x}{d t ^{2}} + \frac{d x}{d t} + x = 0

9 y^{^{''}} - 18 y^{^{'}} + 34 y = 0

y^{^{''}} + \frac{49}{3} y = 0, y (0) = \frac{π}{8}, y^{^{'}} (0) = 0

y^{^{''}} - 2 y^{^{'}} + 10 y = 0, y (0) = 0, y^{^{'}} (0) = - 4

y^{^{''''}} + 2 y^{^{'''}} + y^{^{''}} + 8 y^{^{'}} - 12 y = 0