x^{''}+4.9*x=0,x(0)=0.087,x^'(0)=0

Lösung

x^{^{''}} + 4.9 \cdot x = 0, x (0) = 0.087, x^{^{'}} (0) = 0

x = 0.087 cos (\frac{7 t}{10})

Schritte zur Lösung

x^{''} (t) + 4.9 \cdot x = 0

Solve linear ODE:

x = 0.087 cos (\frac{7 t}{10})

x = 0.087 cos (\frac{7 t}{10})

x^{^{''}} - 2 x^{^{'}} + x = 0, x (0) = 0, x^{^{'}} (0) = 1

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = - 3

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 12 y = 0, y (0) = 0, y^{^{'}} (0) = 4

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 8 y^{^{'}} + 41 y = 0, y (0) = 3, y^{^{'}} (0) = - 11