y^{''}-25y=0,y(0)=0,y^'(0)=20

Lösung

y^{^{''}} - 25 y = 0, y (0) = 0, y^{^{'}} (0) = 20

y = 2 e^{5 t} - 2 e^{- 5 t}

Schritte zur Lösung

y^{''} (t) - 25 y = 0

Solve linear ODE:

y = 2 e^{5 t} - 2 e^{- 5 t}

y = 2 e^{5 t} - 2 e^{- 5 t}

y^{^{''}} + 6 y^{^{'}} + 34 y = 0, y (0) = 2, y^{^{'}} (0) = - 4

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (1) = 1

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = e^{- 3 x}

2 y^{^{''}} - 7 y^{^{'}} + 5 y = 0, y (0) = 4, y^{^{'}} (0) = 5.5

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (0) = 5, y^{^{'}} (0) = - 5