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Beliebt Rechnen >

linear 2y^{''}+16y^'+82y=0

Lösung

linear

2 y^{^{''}} + 16 y^{^{'}} + 82 y = 0

Lösung

y = e^{- 4 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

Schritte zur Lösung

2 y^{''} (t) + 16 y^{'} (t) + 82 y = 0

Solve linear ODE:

y = e^{- 4 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

y = e^{- 4 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

Graph

Beliebte Beispiele

y^{''''}-y^{'''}+y^{''}=0

y^{^{''''}} - y^{^{'''}} + y^{^{''}} = 0

121y^{''}+198y^'+80y=0

121 y^{^{''}} + 198 y^{^{'}} + 80 y = 0

2y^{'''}+7y^{''}+4y^'-4y=0

2 y^{^{'''}} + 7 y^{^{''}} + 4 y^{^{'}} - 4 y = 0

y^{''}+25y^'+2500y=0

y^{^{''}} + 25 y^{^{'}} + 2500 y = 0

3y^{''}-2y+4y^'=0

3 y^{^{''}} - 2 y + 4 y^{^{'}} = 0