4y^{''}-68y^'+289y=0

Lösung

4 y^{^{''}} - 68 y^{^{'}} + 289 y = 0

y = c_{1} e^{\frac{17 t}{2}} + c_{2} e^{\frac{17 t}{2}} t

Schritte zur Lösung

4 y^{''} (t) - 68 y^{'} (t) + 289 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{17 t}{2}} + c_{2} e^{\frac{17 t}{2}} t

y = c_{1} e^{\frac{17 t}{2}} + c_{2} e^{\frac{17 t}{2}} t

y^{^{''}} + 9 y + y = 0, y (0) = 0.16, y^{^{'}} (0) = 0

y^{^{''}} - 7 y^{^{'}} - 2 y = 0

2 y^{^{''}} + 14 y^{^{'}} + 8 y = 0, y (0) = 5, y^{^{'}} (0) = 0

4 y^{^{''}} + 7 y^{^{'}} + 3 y = 0

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (- 1) = 5, y^{^{'}} (- 1) = 2