15x^{''}+44x=0

Lösung

15 x^{^{''}} + 44 x = 0

x = c_{1} cos (\frac{2 11 t}{15}) + c_{2} sin (\frac{2 11 t}{15})

Schritte zur Lösung

15 x^{''} (t) + 44 x = 0

Solve linear ODE:

x = c_{1} cos (\frac{2 11 t}{15}) + c_{2} sin (\frac{2 11 t}{15})

x = c_{1} cos (\frac{2 11 t}{15}) + c_{2} sin (\frac{2 11 t}{15})

x^{^{''}} - 7 x^{^{'}} + 10 x = 0

\frac{3}{4} x^{^{''}} + 9 x = 0

y^{^{''}} - 12 y^{^{'}} + 36 y = 0, y (0) = 6, y^{^{'}} (0) = 1

y^{^{''}} + 6 y^{^{'}} + 35 y = 0

(4 D^{3} - 15 D^{2} + 5 D + 6) y = 0