y^{''}+y^'=0,y^'(0)=1

Lösung

y^{^{''}} + y^{^{'}} = 0, y^{^{'}} (0) = 1

y = c_{1} - e^{- t}

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = 0

Solve linear ODE:

y = c_{1} - e^{- t}

y = c_{1} - e^{- t}

3 y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 6, y^{^{'}} (0) = - 18

\frac{3}{16} y^{^{''}} + 12 y = 0, y (0) = \frac{2}{3}, y^{^{'}} (0) = - 3

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = 1, y^{^{'}} (0) = 3

y^{^{''}} + 4 y^{^{'}} + (a^{2} - 2) y = 0

l in e a r y^{^{''''}} - y = 0