y^{'''}+4y^{''}-25y^'-28y=0

Lösung

y^{^{'''}} + 4 y^{^{''}} - 25 y^{^{'}} - 28 y = 0

y = c_{1} e^{- t} + c_{2} e^{4 t} + c_{3} e^{- 7 t}

Schritte zur Lösung

y^{'''} (t) + 4 y^{''} (t) - 25 y^{'} (t) - 28 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{4 t} + c_{3} e^{- 7 t}

y = c_{1} e^{- t} + c_{2} e^{4 t} + c_{3} e^{- 7 t}

y^{^{''}} + 3 y^{^{'}} + 6 \cdot y = 0, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 8.1, y^{^{'}} (0) = 3.9

y^{^{'''}} + y^{^{''}} - 24 y^{^{'}} + 36 y = 0

36 y^{^{''}} - 132 y^{^{'}} + 121 y = 0, y (0) = 5, y^{^{'}} (0) = 5

y^{^{'''}} - 4 y^{^{''}} + y^{^{'}} + 3 y = 0