f^{''}(t)=f(t)

Lösung

f^{^{''}} (t) = f (t)

f (t) = c_{1} e^{t} + c_{2} e^{- t}

Schritte zur Lösung

f^{''} (t) = f (t)

Solve linear ODE:

f (t) = c_{1} e^{t} + c_{2} e^{- t}

f (t) = c_{1} e^{t} + c_{2} e^{- t}

y^{^{''}} - 4 y^{^{'}} + 5 y = 1 + t, y (0) = 0, y^{^{'}} (0) = 4

y^{^{''}} - 2 y + 3 = 0

(d + 1)^{2} \cdot y = 2 e^{- 2} x

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e^{- 4} x

y^{^{''}} + 9 y = sin^{2} (t)