u^{''}((x))/x+b^2\H(x)((x))/x =0

Lösung

u^{^{''}} \frac{( x )}{x} + b^{2} H (x) \frac{( x )}{x} = 0

u (x) = \int \int - b^{2} H (x) d x d x

Schritte zur Lösung

u^{''} (x) \frac{( x )}{x} + b^{2} H (x) \frac{( x )}{x} = 0

Isoliere

u^{''} (x) : u^{''} (x) = - b^{2} H (x)

Löse

u^{''} (x) = - b^{2} H (x) : u^{'} (x) = \int - b^{2} H (x) d x

Löse

u^{'} (x) = \int - b^{2} H (x) d x : u (x) = \int \int - b^{2} H (x) d x d x

u (x) = \int \int - b^{2} H (x) d x d x

(d^{2} - 6 d + 9) y = 0

x^{^{'''}} - 2 x^{^{''}} = 0

(x + 1) y^{^{'}} = y^{2}

y^{^{'}} x^{2} = y

x^{^{'}} = 4 x + 2 e^{t} \cdot x