(dy)/(dx)=(y^2)/(x-1)

解答

\frac{d y}{d x} = \frac{y ^{2}}{x - 1}

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

求解步骤

\frac{d y}{d x} = \frac{y ^{2}}{x - 1}

求解可分离方程:

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

y = - \frac{1}{ln ( - 1 + x ) + c _{1}}

\frac{\partial}{\partial y} (x^{2} - 3 x y + y^{2})

d er i v a t i v e f (x) = 2 x^{2} - x

\int \frac{1}{t ^{2} - 2 t + 26} d t

y^{^{'}} + y^{2} = 0

\int_{\frac{1}{2}}^{5} 12 x ln (2 x) d x