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Popular Calculus >

(dv)/(dt)= 1/(t^2)

Solution

\frac{d v}{d t} = \frac{1}{t ^{2}}

Solution

v = - \frac{1}{t} + c_{1}

Solution steps

\frac{d v}{d t} = \frac{1}{t ^{2}}

Substitute

\frac{d v}{d t}

with

v^{'} (t)

v^{^{'}} (t) = \frac{1}{t ^{2}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

v = \int \frac{1}{t ^{2}} d t

\int \frac{1}{t ^{2}} d t = - \frac{1}{t} + c_{1}

v = - \frac{1}{t} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (dv)/(dt)= 1/(t^2) ?
The solution for (dv)/(dt)= 1/(t^2) is v=-1/t+c_{1}