What is the derivative of 18cos(x)+9sin^2(x) ?

The derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)

What is the first derivative of 18cos(x)+9sin^2(x) ?

The first derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

18 cos (x) + 9 sin^{2} (x)

- 18 sin (x) + 9 sin (2 x)

Solution steps

\frac{d}{d x} (18 cos (x) + 9 sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (18 cos (x)) + \frac{d}{d x} (9 sin^{2} (x))

\frac{d}{d x} (18 cos (x)) = - 18 sin (x)

\frac{d}{d x} (9 sin^{2} (x)) = 9 sin (2 x)

= - 18 sin (x) + 9 sin (2 x)

What is the derivative of 18cos(x)+9sin^2(x) ?
The derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)
What is the first derivative of 18cos(x)+9sin^2(x) ?
The first derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)