What is the solution for ty^'+(t+1)y=t,y(ln(2))=1 ?

The solution for ty^'+(t+1)y=t,y(ln(2))=1 is y=1-1/t+2/(e^tt)

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ty^'+(t+1)y=t,y(ln(2))=1

t y^{^{'}} + (t + 1) y = t, y (ln (2)) = 1

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

Solution steps

t y^{'} (t) + (t + 1) y = t

Solve linear ODE:

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

What is the solution for ty^'+(t+1)y=t,y(ln(2))=1 ?
The solution for ty^'+(t+1)y=t,y(ln(2))=1 is y=1-1/t+2/(e^tt)