What is the tangent of f(x)=(1+2x)^{11},(0,1) ?

The tangent of f(x)=(1+2x)^{11},(0,1) is y=22x+1

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tangent of f(x)=(1+2x)^{11},(0,1)

tangent of

f (x) = (1 + 2 x)^{11}, (0, 1)

y = 22 x + 1

Solution steps

Find the slope of

f (x) = (1 + 2 x)^{11} : \frac{df ( x )}{d x} = 22 (1 + 2 x)^{10}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 22

Find the line with slope m=

22

and passing through

(0, 1) : y = 22 x + 1

y = 22 x + 1

What is the tangent of f(x)=(1+2x)^{11},(0,1) ?
The tangent of f(x)=(1+2x)^{11},(0,1) is y=22x+1