What is the tangent of f(x)=1-3x^{[2]},\at x=0 ?

The tangent of f(x)=1-3x^{[2]},\at x=0 is y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=1-3x^{[2]},\at x=0

tangent of

f (x) = 1 - 3 x^{[2]}, at x = 0

y = 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

f (x) = 1 - 3 x^{[2]} : \frac{df ( x )}{d x} = - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(0, 1) : y = 1

y = 1

What is the tangent of f(x)=1-3x^{[2]},\at x=0 ?
The tangent of f(x)=1-3x^{[2]},\at x=0 is y=1