derivative of sqrt(4x^2-5)

Lösung

\frac{d}{d x} (4 x^{2} - 5)

\frac{4 x}{4 x ^{2} - 5}

Schritte zur Lösung

\frac{d}{d x} (4 x^{2} - 5)

Wende die Kettenregel an:

\frac{1}{2 4 x ^{2} - 5} \frac{d}{d x} (4 x^{2} - 5)

= \frac{1}{2 4 x ^{2} - 5} \frac{d}{d x} (4 x^{2} - 5)

\frac{d}{d x} (4 x^{2} - 5) = 8 x

= \frac{1}{2 4 x ^{2} - 5} \cdot 8 x

Vereinfache

\frac{1}{2 4 x ^{2} - 5} \cdot 8 x : \frac{4 x}{4 x ^{2} - 5}

= \frac{4 x}{4 x ^{2} - 5}

d er i v a t i v e y = 3 x^{3} - 10 x - \frac{4}{x ^{3}}

\frac{\partial}{\partial x} (\frac{3 x y}{x ^{4} + y ^{4}})

\frac{\partial}{\partial x} (x + 2 y + 1)

h \to 0 lim (\frac{( 2 + h ) ^{2} - 8}{h})

\frac{\partial}{\partial x} (ln (x^{2}))