What is area (sec^2(x))/2 ,2cos^2(x) ?

The answer to area (sec^2(x))/2 ,2cos^2(x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area (sec^2(x))/2 ,2cos^2(x)

area

\frac{sec ^{2} ( x )}{2}, 2 cos^{2} (x)

diverges

Solution steps

Apply the area formula:

\int_{- \frac{5 π}{4}}^{\frac{5 π}{4}} \frac{sec ^{2} ( x )}{2} - 2 cos^{2} (x) d x

Solve

\int_{- \frac{5 π}{4}}^{\frac{5 π}{4}} \frac{sec ^{2} ( x )}{2} - 2 cos^{2} (x) d x :

diverges

The area is:

= diverges

What is area (sec^2(x))/2 ,2cos^2(x) ?
The answer to area (sec^2(x))/2 ,2cos^2(x) is diverges