integral of e^{sqrt(3x+9)}

Lösung

\int e^{3 x + 9} d x

\frac{2}{3} (e^{3 x + 9} 3 x + 9 - e^{3 x + 9}) + C

Schritte zur Lösung

\int e^{3 x + 9} d x

Wende U-Substitution an

= \int \frac{2 e ^{u} u}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{3} \cdot \int e^{u} u d u

Wende die partielle Integration an

= \frac{2}{3} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{2}{3} (e^{u} u - e^{u})

Setze in

u = 3 x + 9

ein

= \frac{2}{3} (e^{3 x + 9} 3 x + 9 - e^{3 x + 9})

Füge eine Konstante zur Lösung hinzu

= \frac{2}{3} (e^{3 x + 9} 3 x + 9 - e^{3 x + 9}) + C

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