y^{''}-1/x y^'+1/(x^2)y= 2/x

解答

y^{^{''}} - \frac{1}{x} y^{^{'}} + \frac{1}{x ^{2}} y = \frac{2}{x}

y = c_{1} x + c_{2} ln (x) x + x ln^{2} (x)

求解步骤

y^{''} (x) - \frac{1}{x} y^{'} (x) + \frac{1}{x ^{2}} y = \frac{2}{x}

求解线性方程:

y = c_{1} x + c_{2} ln (x) x + x ln^{2} (x)

y = c_{1} x + c_{2} ln (x) x + x ln^{2} (x)

\frac{d}{d t} (5 t^{2})

x \to 2 π - lim (csc (x))

\frac{d}{d x} ((1 + 2 x)^{10})

(1 - x^{2}) y^{^{'}} = 2 y

\int_{0}^{3} \frac{1}{9 + x ^{2}} d x