What is (\partial)/(\partial u)(2cos(u)) ?

The answer to (\partial)/(\partial u)(2cos(u)) is -2sin(u)

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(\partial)/(\partial u)(2cos(u))

\frac{\partial}{\partial u} (2 cos (u))

- 2 sin (u)

Solution steps

\frac{\partial}{\partial u} (2 cos (u))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= 2 (- sin (u))

Simplify

= - 2 sin (u)

What is (\partial)/(\partial u)(2cos(u)) ?
The answer to (\partial)/(\partial u)(2cos(u)) is -2sin(u)