What is the integral of (3x+1)^5 ?

The integral of (3x+1)^5 is 1/18 (3x+1)^6+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (3x+1)^5

\int (3 x + 1)^{5} d x

\frac{1}{18} (3 x + 1)^{6} + C

Solution steps

\int (3 x + 1)^{5} d x

Apply u-substitution

= \int \frac{u ^{5}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u^{5} d u

Apply the Power Rule

= \frac{1}{3} \cdot \frac{u ^{6}}{6}

Substitute back

u = 3 x + 1

= \frac{1}{3} \cdot \frac{( 3 x + 1 ) ^{6}}{6}

Simplify

\frac{1}{3} \cdot \frac{( 3 x + 1 ) ^{6}}{6} : \frac{1}{18} (3 x + 1)^{6}

= \frac{1}{18} (3 x + 1)^{6}

Add a constant to the solution

= \frac{1}{18} (3 x + 1)^{6} + C