What is the tangent of 4x^2+y^2=25,(2,3) ?

The tangent of 4x^2+y^2=25,(2,3) is y=-8/3 x+25/3

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tangent of 4x^2+y^2=25,(2,3)

tangent of

4 x^{2} + y^{2} = 25, (2, 3)

y = - \frac{8}{3} x + \frac{25}{3}

Solution steps

Find the slope of

4 x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{4 x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{8}{3}

Find the line with slope m=

- \frac{8}{3}

and passing through

(2, 3) : y = - \frac{8}{3} x + \frac{25}{3}

y = - \frac{8}{3} x + \frac{25}{3}

What is the tangent of 4x^2+y^2=25,(2,3) ?
The tangent of 4x^2+y^2=25,(2,3) is y=-8/3 x+25/3