What is the solution for y^{'''}+3y^{''}+2y^'=0 ?

The solution for y^{'''}+3y^{''}+2y^'=0 is y=c_{1}+c_{2}e^{-t}+c_{3}e^{-2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}+3y^{''}+2y^'=0

y^{^{'''}} + 3 y^{^{''}} + 2 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- t} + c_{3} e^{- 2 t}

Solution steps

y^{'''} (t) + 3 y^{''} (t) + 2 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + c_{3} e^{- 2 t}

y = c_{1} + c_{2} e^{- t} + c_{3} e^{- 2 t}

What is the solution for y^{'''}+3y^{''}+2y^'=0 ?
The solution for y^{'''}+3y^{''}+2y^'=0 is y=c_{1}+c_{2}e^{-t}+c_{3}e^{-2t}