What is the limit as t approaches 2 of (2t)/(4-t^2) ?

The limit as t approaches 2 of (2t)/(4-t^2) is diverges

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limit as t approaches 2 of (2t)/(4-t^2)

t \to 2 lim (\frac{2 t}{4 - t ^{2}})

diverges

Solution steps

t \to 2 lim (\frac{2 t}{4 - t ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 2 + lim (\frac{2 t}{4 - t ^{2}}) = - \infty

t \to 2 - lim (\frac{2 t}{4 - t ^{2}}) = \infty

= diverges

What is the limit as t approaches 2 of (2t)/(4-t^2) ?
The limit as t approaches 2 of (2t)/(4-t^2) is diverges