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Popular Calculus >

(e^x-1)^'

Solution

(e^{x} - 1)^{^{'}}

Solution

e^{x}

Solution steps

(e^{x} - 1)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (e^{x})^{^{'}} - 1^{^{'}}

(e^{x})^{'} = e^{x}

1^{'} = 0

= e^{x} - 0

Simplify

= e^{x}

Graph

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Frequently Asked Questions (FAQ)

What is the (e^x-1)^' ?
The (e^x-1)^' is e^x
What is the first (e^x-1)^' ?
The first (e^x-1)^' is e^x