What is (\partial)/(\partial x)((x-3y)/(x^2+y^2)) ?

The answer to (\partial)/(\partial x)((x-3y)/(x^2+y^2)) is (-x^2+6xy+y^2)/((x^2+y^2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)((x-3y)/(x^2+y^2))

\frac{\partial}{\partial x} (\frac{x - 3 y}{x ^{2} + y ^{2}})

\frac{- x ^{2} + 6 x y + y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{x - 3 y}{x ^{2} + y ^{2}})

Treat

y

as a constant

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial x} ( x - 3 y ) ( x ^{2} + y ^{2} ) - \frac{\partial}{\partial x} ( x ^{2} + y ^{2} ) ( x - 3 y )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x - 3 y) = 1

\frac{\partial}{\partial x} (x^{2} + y^{2}) = 2 x

= \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 x ( x - 3 y )}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 x ( x - 3 y )}{( x ^{2} + y ^{2} ) ^{2}} : \frac{- x ^{2} + 6 x y + y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{- x ^{2} + 6 x y + y ^{2}}{( x ^{2} + y ^{2} ) ^{2}}

What is (\partial)/(\partial x)((x-3y)/(x^2+y^2)) ?
The answer to (\partial)/(\partial x)((x-3y)/(x^2+y^2)) is (-x^2+6xy+y^2)/((x^2+y^2)^2)