What is the integral of arccos(3x) ?

The integral of arccos(3x) is xarccos(3x)-1/3 sqrt(1-9x^2)+C

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integral of arccos(3x)

\int arccos (3 x) d x

x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2} + C

Solution steps

\int arccos (3 x) d x

Apply Integration By Parts

= x arccos (3 x) - \int - \frac{3 x}{1 - 9 x ^{2}} d x

\int - \frac{3 x}{1 - 9 x ^{2}} d x = \frac{1}{3} 1 - 9 x^{2}

= x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2}

Add a constant to the solution

= x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2} + C

What is the integral of arccos(3x) ?
The integral of arccos(3x) is xarccos(3x)-1/3 sqrt(1-9x^2)+C