What is the tangent of f(x)=(1+2x)(3-2x),\at x=1 ?

The tangent of f(x)=(1+2x)(3-2x),\at x=1 is y=-4x+7

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tangent of f(x)=(1+2x)(3-2x),\at x=1

tangent of

f (x) = (1 + 2 x) (3 - 2 x), at x = 1

y = - 4 x + 7

Solution steps

Find the tangent point:

(1, 3)

Find the slope of

f (x) = (1 + 2 x) (3 - 2 x) : \frac{df ( x )}{d x} = - 8 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(1, 3) : y = - 4 x + 7

y = - 4 x + 7

What is the tangent of f(x)=(1+2x)(3-2x),\at x=1 ?
The tangent of f(x)=(1+2x)(3-2x),\at x=1 is y=-4x+7