What is the general solution for solvefor x,(d^2x)/(dt^2)+x=(t^2+t)sin(t) ?

The general solution for solvefor x,(d^2x)/(dt^2)+x=(t^2+t)sin(t) is x=(t^2+t)sin(t)-(d^2x)/(dt^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

solvefor x,(d^2x)/(dt^2)+x=(t^2+t)sin(t)

solve for

x, \frac{d ^{2} x}{d t ^{2}} + x = (t^{2} + t) sin (t)

x = (t^{2} + t) sin (t) - \frac{d ^{2} x}{d t ^{2}}

Solution steps

\frac{d ^{2} x}{d t ^{2}} + x = (t^{2} + t) sin (t)

Move

\frac{d ^{2} x}{d t ^{2}}

to the right side

x = (t^{2} + t) sin (t) - \frac{d ^{2} x}{d t ^{2}}

What is the general solution for solvefor x,(d^2x)/(dt^2)+x=(t^2+t)sin(t) ?
The general solution for solvefor x,(d^2x)/(dt^2)+x=(t^2+t)sin(t) is x=(t^2+t)sin(t)-(d^2x)/(dt^2)