What is the tangent of x^4-y^2=7,(2,3) ?

The tangent of x^4-y^2=7,(2,3) is y= 16/3 x-23/3

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tangent of x^4-y^2=7,(2,3)

tangent of

x^{4} - y^{2} = 7, (2, 3)

y = \frac{16}{3} x - \frac{23}{3}

Solution steps

Find the slope of

x^{4} - y^{2} = 7 : \frac{d y}{d x} = \frac{2 x ^{3}}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{16}{3}

Find the line with slope m=

\frac{16}{3}

and passing through

(2, 3) : y = \frac{16}{3} x - \frac{23}{3}

y = \frac{16}{3} x - \frac{23}{3}

What is the tangent of x^4-y^2=7,(2,3) ?
The tangent of x^4-y^2=7,(2,3) is y= 16/3 x-23/3