What is the derivative of 2e^{-x}cos(x) ?

The derivative of 2e^{-x}cos(x) is 2(-e^{-x}cos(x)-e^{-x}sin(x))

What is the first derivative of 2e^{-x}cos(x) ?

The first derivative of 2e^{-x}cos(x) is 2(-e^{-x}cos(x)-e^{-x}sin(x))

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\frac{d}{d x} (2 e^{- x} cos (x))

2 (- e^{- x} cos (x) - e^{- x} sin (x))

Solution steps

\frac{d}{d x} (2 e^{- x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{- x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- x}, g = cos (x)

= 2 (\frac{d}{d x} (e^{- x}) cos (x) + \frac{d}{d x} (cos (x)) e^{- x})

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 ((- e^{- x}) cos (x) + (- sin (x)) e^{- x})

Simplify

= 2 (- e^{- x} cos (x) - e^{- x} sin (x))

What is the derivative of 2e^{-x}cos(x) ?
The derivative of 2e^{-x}cos(x) is 2(-e^{-x}cos(x)-e^{-x}sin(x))
What is the first derivative of 2e^{-x}cos(x) ?
The first derivative of 2e^{-x}cos(x) is 2(-e^{-x}cos(x)-e^{-x}sin(x))