What is the solution for y^{''}+3y^'+0=5 ?

The solution for y^{''}+3y^'+0=5 is y=c_{1}+c_{2}e^{-3t}+(5t)/3

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y^{''}+3y^'+0=5

y^{^{''}} + 3 y^{^{'}} + 0 = 5

y = c_{1} + c_{2} e^{- 3 t} + \frac{5 t}{3}

Solution steps

y^{''} (t) + 3 y^{'} (t) + 0 = 5

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 t} + \frac{5 t}{3}

y = c_{1} + c_{2} e^{- 3 t} + \frac{5 t}{3}

What is the solution for y^{''}+3y^'+0=5 ?
The solution for y^{''}+3y^'+0=5 is y=c_{1}+c_{2}e^{-3t}+(5t)/3