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Popular Calculus >

integral from-1 to 2 of (3x+1)

Solution

\int_{- 1}^{2} (3 x + 1) d x

Solution

\frac{15}{2}

+1

Decimal

7.5

Solution steps

\int_{- 1}^{2} 3 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 3 x d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} 3 x d x = \frac{9}{2}

\int_{- 1}^{2} 1 d x = 3

= \frac{9}{2} + 3

Simplify

\frac{9}{2} + 3 : \frac{15}{2}

= \frac{15}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (3x+1) ?
The integral from-1 to 2 of (3x+1) is 15/2