4y^{''}+9y^'=0

Lösung

4 y^{^{''}} + 9 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{9 t}{4}}

Schritte zur Lösung

4 y^{''} (t) + 9 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{9 t}{4}}

y = c_{1} + c_{2} e^{- \frac{9 t}{4}}

y^{^{''}} + y = 6 sin (2 t) + 4 t cos (2 t)

\frac{d}{d x} (600000 (0.8)^{x})

\int \frac{x ^{4} + 1}{x ^{5} + 4 x ^{3}} d x

n = 1 \sum \infty (- 1)^{n - 1}

\int \frac{3 x + 1}{( x - 2 ) ( x + 3 ) ^{2}} d x