What is the solution for y^'-3/x y=4x^3cos(2x) ?

The solution for y^'-3/x y=4x^3cos(2x) is y=2sin(2x)x^3+c_{1}x^3

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y^'-3/x y=4x^3cos(2x)

y^{^{'}} - \frac{3}{x} y = 4 x^{3} cos (2 x)

y = 2 sin (2 x) x^{3} + c_{1} x^{3}

Solution steps

y^{'} (x) - \frac{3}{x} y = 4 x^{3} cos (2 x)

Solve linear ODE:

y = 2 sin (2 x) x^{3} + c_{1} x^{3}

y = 2 sin (2 x) x^{3} + c_{1} x^{3}

What is the solution for y^'-3/x y=4x^3cos(2x) ?
The solution for y^'-3/x y=4x^3cos(2x) is y=2sin(2x)x^3+c_{1}x^3