What is the tangent of y=x^4+6x^2-x,(1,6) ?

The tangent of y=x^4+6x^2-x,(1,6) is y=15x-9

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tangent of y=x^4+6x^2-x,(1,6)

tangent of

y = x^{4} + 6 x^{2} - x, (1, 6)

y = 15 x - 9

Solution steps

Find the slope of

y = x^{4} + 6 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 12 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 15

Find the line with slope m=

15

and passing through

(1, 6) : y = 15 x - 9

y = 15 x - 9

What is the tangent of y=x^4+6x^2-x,(1,6) ?
The tangent of y=x^4+6x^2-x,(1,6) is y=15x-9