What is the derivative of 16e^{-2x} ?

The derivative of 16e^{-2x} is -32e^{-2x}

What is the first derivative of 16e^{-2x} ?

The first derivative of 16e^{-2x} is -32e^{-2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (16 e^{- 2 x})

- 32 e^{- 2 x}

Solution steps

\frac{d}{d x} (16 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 16 e^{- 2 x} (- 2)

Simplify

= - 32 e^{- 2 x}

What is the derivative of 16e^{-2x} ?
The derivative of 16e^{-2x} is -32e^{-2x}
What is the first derivative of 16e^{-2x} ?
The first derivative of 16e^{-2x} is -32e^{-2x}