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Popular Calculus >

y^'=-x

Solution

y^{^{'}} = - x

Solution

y = - \frac{x ^{2}}{2} + c_{1}

Solution steps

y^{'} (x) = - x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - x d x

\int - x d x = - \frac{x ^{2}}{2} + c_{1}

y = - \frac{x ^{2}}{2} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-x ?
The solution for y^'=-x is y=-(x^2)/2+c_{1}