What is the derivative of 2x-(16/(x^2)) ?

The derivative of 2x-(16/(x^2)) is 2+(32)/(x^3)

What is the first derivative of 2x-(16/(x^2)) ?

The first derivative of 2x-(16/(x^2)) is 2+(32)/(x^3)

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\frac{d}{d x} (2 x - \frac{16}{x ^{2}})

2 + \frac{32}{x ^{3}}

Solution steps

\frac{d}{d x} (2 x - \frac{16}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (\frac{16}{x ^{2}})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{16}{x ^{2}}) = - \frac{32}{x ^{3}}

= 2 - (- \frac{32}{x ^{3}})

Simplify

= 2 + \frac{32}{x ^{3}}

What is the derivative of 2x-(16/(x^2)) ?
The derivative of 2x-(16/(x^2)) is 2+(32)/(x^3)
What is the first derivative of 2x-(16/(x^2)) ?
The first derivative of 2x-(16/(x^2)) is 2+(32)/(x^3)