What is the derivative of x^6+3x^4+7x^2 ?

The derivative of x^6+3x^4+7x^2 is 6x^5+12x^3+14x

What is the first derivative of x^6+3x^4+7x^2 ?

The first derivative of x^6+3x^4+7x^2 is 6x^5+12x^3+14x

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\frac{d}{d x} (x^{6} + 3 x^{4} + 7 x^{2})

6 x^{5} + 12 x^{3} + 14 x

Solution steps

\frac{d}{d x} (x^{6} + 3 x^{4} + 7 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{6}) + \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (7 x^{2})

\frac{d}{d x} (x^{6}) = 6 x^{5}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (7 x^{2}) = 14 x

= 6 x^{5} + 12 x^{3} + 14 x

What is the derivative of x^6+3x^4+7x^2 ?
The derivative of x^6+3x^4+7x^2 is 6x^5+12x^3+14x
What is the first derivative of x^6+3x^4+7x^2 ?
The first derivative of x^6+3x^4+7x^2 is 6x^5+12x^3+14x