What is the tangent of f(x)=-1-9x^2,\at x=3 ?

The tangent of f(x)=-1-9x^2,\at x=3 is y=-54x+80

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tangent of f(x)=-1-9x^2,\at x=3

tangent of

f (x) = - 1 - 9 x^{2}, at x = 3

y = - 54 x + 80

Solution steps

Find the tangent point:

(3, - 82)

Find the slope of

f (x) = - 1 - 9 x^{2} : \frac{df ( x )}{d x} = - 18 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 54

Find the line with slope m=

- 54

and passing through

(3, - 82) : y = - 54 x + 80

y = - 54 x + 80

What is the tangent of f(x)=-1-9x^2,\at x=3 ?
The tangent of f(x)=-1-9x^2,\at x=3 is y=-54x+80