tangent f(x)= 1/(x^2),(2, 1/4)

解答

切线

f (x) = \frac{1}{x ^{2}}, (2, \frac{1}{4})

y = - \frac{1}{4} x + \frac{3}{4}

求解步骤

计算

f (x) = \frac{1}{x ^{2}}

的斜率:

\frac{df ( x )}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

找到斜率 m=

- \frac{1}{4}

且穿过

(2, \frac{1}{4})

的直线:

y = - \frac{1}{4} x + \frac{3}{4}

y = - \frac{1}{4} x + \frac{3}{4}