What is the d/(dt)(e^{3cos(t)+2t^2}) ?

The d/(dt)(e^{3cos(t)+2t^2}) is e^{3cos(t)+2t^2}(-3sin(t)+4t)

What is the first d/(dt)(e^{3cos(t)+2t^2}) ?

The first d/(dt)(e^{3cos(t)+2t^2}) is e^{3cos(t)+2t^2}(-3sin(t)+4t)

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\frac{d}{d t} (e^{3 c o s (t) + 2 t^{2}})

e^{3 c o s (t) + 2 t^{2}} (- 3 sin (t) + 4 t)

Solution steps

\frac{d}{d t} (e^{3 c o s (t) + 2 t^{2}})

Apply the chain rule:

e^{3 c o s (t) + 2 t^{2}} \frac{d}{d t} (3 cos (t) + 2 t^{2})

= e^{3 c o s (t) + 2 t^{2}} \frac{d}{d t} (3 cos (t) + 2 t^{2})

\frac{d}{d t} (3 cos (t) + 2 t^{2}) = - 3 sin (t) + 4 t

= e^{3 c o s (t) + 2 t^{2}} (- 3 sin (t) + 4 t)

What is the d/(dt)(e^{3cos(t)+2t^2}) ?
The d/(dt)(e^{3cos(t)+2t^2}) is e^{3cos(t)+2t^2}(-3sin(t)+4t)
What is the first d/(dt)(e^{3cos(t)+2t^2}) ?
The first d/(dt)(e^{3cos(t)+2t^2}) is e^{3cos(t)+2t^2}(-3sin(t)+4t)