What is the derivative of e^{x^2-4}+2x+9 ?

The derivative of e^{x^2-4}+2x+9 is 2e^{x^2-4}x+2

What is the first derivative of e^{x^2-4}+2x+9 ?

The first derivative of e^{x^2-4}+2x+9 is 2e^{x^2-4}x+2

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\frac{d}{d x} (e^{x^{2} - 4} + 2 x + 9)

2 e^{x^{2} - 4} x + 2

Solution steps

\frac{d}{d x} (e^{x^{2} - 4} + 2 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x^{2} - 4}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (9)

\frac{d}{d x} (e^{x^{2} - 4}) = e^{x^{2} - 4} \cdot 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (9) = 0

= e^{x^{2} - 4} \cdot 2 x + 2 + 0

Simplify

= 2 e^{x^{2} - 4} x + 2

What is the derivative of e^{x^2-4}+2x+9 ?
The derivative of e^{x^2-4}+2x+9 is 2e^{x^2-4}x+2
What is the first derivative of e^{x^2-4}+2x+9 ?
The first derivative of e^{x^2-4}+2x+9 is 2e^{x^2-4}x+2