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Popular Calculus >

y^'=(x+1)*(y+1)

Solution

y^{^{'}} = (x + 1) \cdot (y + 1)

Solution

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Solution steps

y^{'} (x) = (x + 1) \cdot (y + 1)

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+1)*(y+1) ?
The solution for y^'=(x+1)*(y+1) is y=e^{(x^2)/2+x+c_{1}}-1