What is the derivative of x/(\sqrt[3]{x^2+4}) ?

The derivative of x/(\sqrt[3]{x^2+4}) is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}

What is the first derivative of x/(\sqrt[3]{x^2+4}) ?

The first derivative of x/(\sqrt[3]{x^2+4}) is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}

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Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d x}{d x} = 1

Simplify

What is the derivative of x/(\sqrt[3]{x^2+4}) ?
The derivative of x/(\sqrt[3]{x^2+4}) is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}
What is the first derivative of x/(\sqrt[3]{x^2+4}) ?
The first derivative of x/(\sqrt[3]{x^2+4}) is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}