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人気のある微分積分 >

integral from 0 to 2 of |x-1|

解

\int_{0}^{2} ∣ x - 1 ∣ d x

解

1

解答ステップ

\int_{0}^{2} ∣ x - 1 ∣ d x

絶対数を排除する

= \int_{0}^{1} - x + 1 d x + \int_{1}^{2} x - 1 d x

\int_{0}^{1} - x + 1 d x = \frac{1}{2}

\int_{1}^{2} x - 1 d x = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

簡素化

\frac{1}{2} + \frac{1}{2} : 1

= 1

グラフ

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