What is the solution for y^{''}+y=cos(2x) ?

The solution for y^{''}+y=cos(2x) is y=c_{1}cos(x)+c_{2}sin(x)-1/3 cos(2x)

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y^{''}+y=cos(2x)

y^{^{''}} + y = cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

Solution steps

y^{''} (x) + y = cos (2 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

What is the solution for y^{''}+y=cos(2x) ?
The solution for y^{''}+y=cos(2x) is y=c_{1}cos(x)+c_{2}sin(x)-1/3 cos(2x)